finish up

复习资料/A.aux

@@ -1,23 +0,0 @@
-\relax 
-\providecommand\hyper@newdestlabel[2]{}
-\providecommand*\HyPL@Entry[1]{}
-\HyPL@Entry{0<</S/D>>}
-\@writefile{toc}{\contentsline {section}{\numberline {1}数据表示与存储}{1}{section.1}\protected@file@percent }
-\@writefile{toc}{\contentsline {subsection}{\numberline {1.1}数据的类型及大小}{1}{subsection.1.1}\protected@file@percent }
-\@writefile{lot}{\contentsline {table}{\numberline {1}{\ignorespaces 数据的类型及大小}}{1}{table.1}\protected@file@percent }
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-\@writefile{toc}{\contentsline {subsection}{\numberline {1.3}补码}{1}{subsection.1.3}\protected@file@percent }
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复习资料/A.tex

@@ -33,7 +33,7 @@
 \pagestyle{myfancypagestyle}
 
 \tcbuselibrary{listings}
-\tcbset{colback=white,boxrule=0.3mm,enhanced}
+\tcbset{colback=white,boxrule=0.3mm,enhanced,size=small}
 
 \lstset{basicstyle=\ttfamily,columns=fullflexible}
 
@@ -45,7 +45,6 @@
 \section{数据表示与存储} 
 \subsection{数据的类型及大小}
 \begin{table}[h]
-    \caption{数据的类型及大小}
     \begin{tabular}{|c|c|c|c|c|}
     \hline
     类型    & 字节数 & 最小值 & 最大值(signed) & 最大值(unsigned) \\ \hline
@@ -140,7 +139,7 @@ T: 用 $n$ 位表示数字
 
 $\text{(unsigned)} \ \text{exp} \ = \ E \ + \text{Bias}$
 
-$\text{Bias (偏置值)} = 2^{k-1}-1$ , k 为 $exp$ 的二进制位数
+$\text{Bias (偏置值)} = 2^{k-1}-1$ , \(k\) 为 exp 的二进制位数
 
 \begin{multicols}{2}
     例1:十进制整数$\rightarrow$二进制浮点数
@@ -240,7 +239,15 @@ frac \(\ne 00\dots0\) 表示 NaN
 \end{table}
 
 \pagebreak
-\vspace{-0.5em}
+
+\InsertBoxR{0}{\tcboxmath{\begin{matrix}
+    \text{寻址模式} & \text{p. 121} \\
+    \text{栈帧结构} & \text{p. 164} \\
+    \text{gdb 操作} & \text{p. 194} \\
+\end{matrix}}\hspace{2cm}}
+
+\vspace{-1.5em}
+
 \section{程序的机器级表示}
 
 \subsection{计算数组元素的地址}
@@ -256,29 +263,17 @@ frac \(\ne 00\dots0\) 表示 NaN
 2 \ leaq (\%rdi,\%rax,\$k), \%rax  \\
 3 \ movl (\%rax,\%rdx,\$k), \%rax  \\
 }
-结果为 \texttt{D+ k $\cdot$ C $\cdot$ i + k $\cdot$ j} \\
+结果为 \texttt{D + k $\cdot$ C $\cdot$ i + k $\cdot$ j} \\
 即 \texttt{D + sizeof(T) $\times$ (C $\cdot$ i + j)}
 \end{multicols}
 
-\vspace{-1cm}
+\vspace{-2.5em}
-
-\subsection{其他内容}
-\vspace{-2mm}
-\begin{table}[h]
-    \begin{tabular}{c|c|c|c} \hline
-    内容 & 操作数计算方式& 栈&gdb常用操作\\ \hline
-    页码 & P121&P164&P194 \\
-
-    \hline
-\end{tabular}
-\end{table}
-
-\vspace{-2em}
 
 \section{链接}
-\vspace{-1em}
+\vspace{-1.5em}
 \subsection{符号表 (.symtab)}
 \vspace{-1em}
+
 \begin{table}[h]
     \begin{tabular}{l|c|c|c|l}
     \hline
@@ -308,9 +303,11 @@ frac \(\ne 00\dots0\) 表示 NaN
     & --- & --- & --- & \makecell[l]{链接不涉及静态函数\\链接不涉及非静态局部变量} \\ \hline
     \end{tabular}
 \end{table}
+
 \vspace{-2em}
 \subsection{链接顺序}
 \vspace{-0.5em}
+
 \texttt{\$ gcc -static -o prog2c main2.o ./libvector.a} \\
 E 将被合并以组成可执行文件的所有目标文件集合\\
 U 当前所有未解析的引用符号的集合\\
@@ -318,12 +315,23 @@ D 当前所有定义符号的集合\\
 开始 E、U、D为空，首先扫描 \texttt{main2.o}，将其加入 E，将未找到的符号加入 U, 定义的符号加入 D。 \\
 再扫描 \texttt{./libvector.a}，将匹配到的 U 中的符号转移到 D 并加入到 E， 同时将未找到的符号加入 U。 \\
 最后搜索标准库 \texttt{libc.a}，处理完\texttt{libc.a}时，U一定是空的，D中符号唯一，否则错误。
+
 \vspace{-1em}
 \subsection{重定位}
 \vspace{-0.5em}
-PC相对地址下重定位值计算公式：\\
+
-\texttt{ADDR(r.symbol)-((ADDR(.text)+r.offset)-r.addend)}\\
+\begin{itemize}
-在asm中表示为 \texttt{4004de: e8 \underbar{05 00 00 00} \quad callq 4004e8 <sum>}
+    \item 重定位 PC 相对引用(\texttt{R\_X86\_64\_PC32}): \\
+    重定位值 \( =\texttt{ADDR(r.symbol)} - \underbrace{\left(\texttt{ADDR(.text)} + \texttt{r.offset}\right)}_{\text{重定位值的地址}} + \texttt{r.addend}\)
+
+    在asm中表示为 \texttt{4004de: e8 \underbar{05 00 00 00} \quad callq 4004e8 <sum>}
+
+    \item 重定位绝对引用(\texttt{R\_X86\_64\_32}): \\
+    重定位值 = \(\texttt{ADDR(r.symbol)} + \texttt{r.addend}\) \\
+    在asm中直接以其绝对地址表示\texttt{4004d9: bf \underbar{18 10 60 00} \quad mov \$0x601018 \%edi}
+
+\end{itemize}
+
 
 \newpage